Emacs Regex Quirk: Matching beginning/end of line/string

Perm URL with updates: http://xahlee.org/emacs/emacs_regex_begin_end_line_string.html

, 2011-09-29, …, 2011-11-28

This page is a tutorial on emacs regex. Suppose you want to write a function that removes spaces in front of a string. You'd use a regex like this:

(replace-regexp-in-string "^ +" "" myString)

Here, the ^ means beginning of string, right?


In emacs regex, ^ matches beginning of string, but also beginning of each line in the string. Try to evaluate the following (place cursor at end then call eval-last-sexp.):

(replace-regexp-in-string "^ +" "•"
    (1) this
    (2) that

Here's the result:

•(1) this
•(2) that

To match just the beginning of a string, use \`. Like this:

;; Remove space/tab/newline in beginning myStr
(replace-regexp-in-string "\\`[ \t\n]*" "" myStr)

Similarly, the $ matches the endings of {buffer, string, line}. To just match ending of {buffer, string}, use \'. In lisp code, you'll need to double the backslash.


Special Regex CharMatches
^beginning of {line, string, buffer}
$end of {line, string, buffer}
\`beginning of {string, buffer}
\'end of {string, buffer}

See also: Text Pattern Matching in Emacs (emacs regex tutorial).

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