Lisp read-from-minibuffer Propels Deep Questions

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slightly frustrated with emacs lisp “read-from-minibuffer”. Spent now about a hour on this.

what i want is simple, like this:

 (format "Directory (default %s):" default-directory) default-directory )

prompt user to enter a dir, with default of current dir.

however, according to inline doc of “read-from-minibuffer”, the second arg for default input is obsolete. Instead, you have to use the 6th arg. (info "(elisp) Text from Minibuffer") Quote:

(read-from-minibuffer PROMPT &optional INITIAL-CONTENTS KEYMAP READ

the doc is long so i won't paste here. See it by calling “describe-function”.

Now, so i do:

 (format "Directory (default %s):" default-directory) nil nil nil nil default-directory)

doesn't work. Read the doc again, it turns out that the 4th arg must be true in order for the default value to work, else you get empty string if the user just press Enter.

So i do:

 (format "Directory (default %s):" default-directory) nil nil t nil default-directory)

No go! because if the 4th arg is true, it means the input as a string will be fed to lisp reader, then interpreted as a lisp object. Hot damn. This means, if you want a string, you have to feed it "\"mystring\"". (the outter string makes it a lisp string to be fed to lisp reader, then, the inner string gets you a lisp string object)

So, now i have to do this:

 (format "Directory (default %s):" default-directory) nil nil t nil (format "\"%s\"" default-directory) )

But no! Because, now if user actually enter a value, e.g. type mary, lisp reader freaks out. Again, it doesn't undertand what the letter sequence mary is. It wants a string "\"mary\"". So, user will have to actually type "mary" for this to work.


This line is supposed to be done in 20 seconds. I think i've spent 40 min on this. Now, my mind wanders to the deep question of humanity….


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